-2n^2+33n-16=0

Solution for -2n^2+33n-16=0 equation:

-2n^2+33n-16=0

a = -2; b = 33; c = -16;
Δ = b2-4ac
Δ = 332-4·(-2)·(-16)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-31}{2*-2}=\frac{-64}{-4}
=+16
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+31}{2*-2}=\frac{-2}{-4}
=1/2
$